Hi. I need help with this question : Question : y is such that and :
I). What range of values satisfies both inequalities ?
II). Hence, express
in the form of
where a and b are both integers.

Please show workings.

9514 1404 393

  -4 ≤ y ≤ 7

Step-by-step explanation:

Solve the inequalities separately, then identify the intersection of the solution sets.

4y -7 ≤ 3y

  y -7 ≤ 0 . . . . . . . subtract 3y

  y ≤ 7 . . . . . . . . . add 7

3y ≤ 5y +8

  0 ≤ 2y +8 . . . . . . subtract 3y

  -8 ≤ 2y . . . . . . . . . subtract 8

  -4 ≤ y . . . . . . . . . . divide by 2

The intersection of the sets y ≤ 7 and -4 ≤ y is given by ...

  -4 ≤ y ≤ 7

the answer is 37

step-by-step explanation:

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!