1) : 2x + 5y = 12 a. (1,?) b. (?, 1) C. (0,?) d. (?, 0)

A. y = 2

B. x = 7/2

C. y = 12/5

D. x = 6

Step-by-step explanation:

A. Determination of y .

2x + 5y = 12

x = 1

2(1) + 5y = 12

2 + 5y = 12

Collect like terms

5y = 12 – 2

5y = 10

Divide both side by 5

y = 10 / 5

y = 2

B. Determination of x

2x + 5y = 12

y = 1

2x + 5(1) = 12

2x + 5 = 12

Collect like terms

2x = 12 – 5

2x = 7

Divide both side by 2

x = 7/2

C. Determination of y

2x + 5y = 12

x = 0

2(0) + 5y = 12

0 + 5y = 12

5y = 12

Divide both side by 5

y = 12/5

D. Determination of x

2x + 5y = 12

y = 0

2x + 5(0) = 12

2x + 0 = 12

2x = 12

Divide both side by 2

x = 12/2

x = 6

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2