how many solutions does the problem c*r*(a+f+t)=21 have if different letters represent different digits

Step-by-step explanation:

Factors of 21 are 1, 3, 7 and 21.

a + f + t cannot be 1 or 3 as it cannot be written as a sum of 3 distinct digits, so it is 7.

The smallest 3 remaining digits are 2, 5 and 6 which add to 13.

So there are no solutions.

12

Step-by-step explanation:

21 = 21 x1 3x7

=1x3 expand over3= 12

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

i have no idea just need points sorry

step-by-step explanation: