Enter the ordered pair for the vertices for 180°,0)(QRST). Q
o
S
IR
O Q' = (-1,-3) R' = (-3,3 ) S'= (0,2)T' =(2, -1)
OQ' = (-1,3) R' = (-3,-3) S'=(0, -2)T' =(2, 1)
Q' = (1, -3) R' =(3,3) S' = (0,2)T' = (-2,-1)

The ordered pair for the vertices for r₍₁₈₀ ₀₎(QRST), is given as follows;

Q' = (-1, -3) R' = (-3, 3) S' = (0, 2) T' = (2, -1)

Step-by-step explanation:

The coordinates of he vertices of the triangle QRST are;

Q(1, 3), R(3, -3), S(0, -2), T(-2, 1)

A rotation of a point with coordinates (x, y) 180° about the origin gives;

The coordinate of the point of the preimage before the rotation = (x, y)

The coordinate of the point of the image after the rotation = (-x, -y)

Therefore we have;

The image of point Q(1, 3) after 180° rotation = Q'(-1, -3)

The image of point R(3, -3) after 180° rotation = R'(-3, 3)

The image of point S(0, -2) after 180° rotation = S'(0, 2)

The image of point T(-2, 1) after 180° rotation = T'(2, -1)

The ordered pair for the vertices for r₍₁₈₀ ₀₎(QRST), is therefore, Q'(-1, -3), R'(-3, 3), S'(0, 2), and T'(2, -1);

Q' = (-1, -3) R' = (-3, 3) S' = (0, 2) T' = (2, -1).

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph