the path of a toy rocket is modelled by the equation y=-x^2+6x+2, where x is the horizontal distance, in metres, travelled and y is the height, in metres, of the toy rocket above the ground. what is the maximum height of the toy rocket? at what horizontal distance does the maximum height occur?

The path of a toy rocket is defined by the relation y=-3x^2+11x+4, where x is the horizontal distance, in meters, traveled and y is the height, in metres, above the ground.

Determine the zeros of the relation.

-3x^2 + 11x + 4 = 0

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3x^2 - 11x -4 = 0

Factor:

3x^2 - 12x + x - 4 = 0

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3x(x-4) + x-4 = 0

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(x-4)(3x+1) = 0

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x = 4 or x = -1/3

f(x) = -3x^2+11x+4

How far has the rocket traveled horizontally when it lands on the ground?

4 ft.

What is the maximum height of the rocket above the ground, to the nearest hundredth of a meter?

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max occurs when x = -b/2a = -11/(2*-3) = 11/6

height = f(11/6) = 14.083 ft

step-by-step explanation:

most likely the answer is a.

alice wins if a total of 5 is rolled. finn wins if a total of 9 is rolled.

i can't solve unless i know what the line is

step-by-step explanation:

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