What are the roots of the equation?
10x2 - 6x + 4 = -3x

(3 +/- i*sqrt(151) / 20 (no real solutions)

Step-by-step explanation:

10x^2 - 6x + 4 = -3x

Add 3x to both sides

10x^2 - 6x + 4 + 3x = -3x + 3x

10x^2 - 6x + 4 + 3x = 0

Add like terms

10x^2 - 3x + 4 = 0

We have to use quadratic formula to find the answers

For this equation, a = 10, b = -3 and c = 4

Note: +/- is plus or minus

Quadratic formula:

x = (-b +/- sqrt(b^2 - 4ac)) / 2a

x = (-(-3) +/- sqrt(-3^2 - 4(10)(4))) / 2(10)

x = (3 +/- sqrt(9 - 160)) / 20

x = (3 +/- sqrt(-151) / 20

x = (3 +/- i*sqrt(151) / 20

if there's a "-" sign inside a square root, it will give you an imaginary number.

Example:

-sqrt(9) = -3

sqrt(-9) = 3i (first you will ignore the "- " sign, then square the number. After finding the square root, take that '-' sign and turn it to an "i")

So for sqrt(-151), 151 is not a perfect square, so you will get a decimal number. Leave it as it is:

sqrt(151). We can't forget about the "-". Turn the minus into a sign.

It will be i*sqrt(151)

Imaginary numbers can't be simplified, so this is the answer.

(3 +/- i*sqrt(151) / 20

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

i believe it is b and c. (side note, i got the same computer from k-12 lol i’m in 8th grade and this is my first year, will it get

step-by-step explanation: