We are given AB / DE. Because the lines are parallel and segment CB crosses both lines, we can consider
segment CB a transversal of the parallel lines. Angles
CED and CBA are corresponding angles of transversal
CB and are therefore congruent, so 2CED ZCBA.
We can state C 2C using the reflexive property.
Therefore, AACB- ADCE by the
O AA similarity theorem.
O SSS similarity theorem.
O AAS similarity theorem.
O ASA similarity theorem.

the answer is b.

step-by-step explanation:

by the trigonometric ratio tangent, tangent equals opposite divided by adjacent.

therefore, tan(50) equals ac/3

multiply each side by 3 to get: ac=3tan(50)

the answer is b.

246

step-by-step explanation:

step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6