Find the dimension of a rectangle whose with is 6 miles less than its length and whose area is 72 square tiles

Length = 12

Width = 6

Step-by-step explanation:

Width = 6 miles less than length;

L = L

W = L - 6

Area = 72 ft²

Area = Length * width

Area = (L * L-6)

Area = L² - 6L

-

L² - 6L = 72

L² - 6L - 72 = 0

L² - 12L + 6L - 72 = 0

L(L - 12) +6(L - 12) = 0

L = 12 or L = - 6

L cannot be negative

Width = L - 6

Width = 12 - 6 = 6

Hence,

Dimension of rectangle :

Length = 12

Width = 6

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

just get this app called photo math it should be able to do those