The point P(0.5, 0) Lies on the curve y = cos π x(a) If Q is the point (x, cos 7rX), use your calc ulator to find the slope of the secant line PQ (correct to six decimal places) for the following values of x:(i) 0 (ii) 0.4 (iii) 0.4 (iv) 0.499 (v) 1 (vi) 0.6 (vii) 0.51 (viii) 0.501(b) Using the results of part (a), guess the value of the slope of the tangent line to the curve at P(0.5, 0).(c) Using the slope from part (b), find an equation of the tangent line to the curve at P(0.5, 0).(d) Sketch the curve , two of the secant lines, and the tangent line.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

answer: 5

step-by-step explanation:

table a is wierd

step-by-step explanation:

6*f