Multiple people counted the number of spectators at a high school swim meet. All counts were between 208208 and 217217, inclusive. Assuming that the exact number of spectators is within that range of numbers, what is the most the percent error could be? Round your answer to the nearest tenth of a percent.

b. 2 and 4

step-by-step explanation:

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answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

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