3 left parenthesis x space minus space 8 right parenthesis greater than negative 4 space plus space x

The solution of the given inequality

          x > 10

Step-by-step explanation:

Step(i):-

Given inequality  

                     3 ( x-8) > -4 + x

Multiply

                   3 x - 24 > -4 +x

subtract 'x' on both sides , we get

                 3 x - 24 - x > - 4 + x - x

        ⇒     2 x - 24 > - 4

Step(ii):-

Adding '2'4' on both sides , we get

        ⇒     2x - 24 + 24 > -4 +24

      ⇒     2 x > 20

Dividing '2' on both sides , we get

                x > 10

Final answer:-

The solution of the given inequality

          x > 10

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐