I need to evaluate h(3)

h(3) = - 1

Step-by-step explanation:

To evaluate h(3), that is x = 3 in the interval x ≥ 1 , then

h(x) = - x + 2 , thus

h(3) = - 3 + 2 = - 1

Then h(3) = - 1

step-by-step explanation:

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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