A placekicker for a football team makes field goals 55% of the time when kicking from the 35-yard line. Assume that field goal attempts can be considered random events. Using the table, what is the probability that the
placekicker will make at least 3 of his next 5 attempts from the 35-yard line?
1
3
4
5
Field Goal
Probability
0
0.02
2
0.27
0.11
0.34
0.21
?
0.34
0.26
O 0.60
O 0.74
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that’s

.34

Step-by-step explanation:

By using the table you would look at 3 (what the question wants which would be the x-value) and the y-value would be the answer.

Or you can use this calculator https://stattrek.com/online-calculator/binomial.aspx

and put in 55% for the success

5 for the amount of trials

and 3 for the success of the trials

calculated and you get .336 or rounded .34

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240