Mrs. Childress has 12 packs of pencils and 8 packs of cap erasers. What is the FEWEST amount of each
she will need to buy in order to have an equal
number packs of both pencils and cap erasers?

4 packs of erasers and 0 packs of pencils

Step-by-step explanation:

To minimize what she needs to buy to end up with the same number of packs of pencils and erasers, she needs to make the number of each to be equal. So the total number of packs should be 12. She all ready has 12 pencil packs and would only need to buy 4 eraser packs

452,489 to the nearest thousand is 452,000

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.