Suppose you can get a higher interest rate on your savings if you maintain a balance of at least $1000 in your savings account. the balance of your account is now $1058. you deposit $44.50 into your account. what is the greatest amount that you can withdraw and still get the higher interest rate?

$102.5

Step-by-step explanation:

∵ The balance of the account = $ 1058,

After depositing $ 44.50 in the account,

Balance of the account = 1058 + 44.50 = $ 1102.5,

Let x be the amount ( in dollars ),

Which is withdrawn from the account,

So, the final balance of the account  = (1102.5-x) dollars

∵ For getting higher interest rate,

Balance ≥ $ 1000,

⇒ 1102.5-x ≥ 1000

⇒ 1102.5 ≥ 1000 + x

⇒ 1102.5 - 1000 ≥ x

⇒ 102.5  ≥ x

Hence, the greatest amount that can withdraw would be $102.5

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v