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Given that z1=−34+36iz1=−34+36i and z2=21 +−6iz2=21+−6i, then z2−z1=x+yiz2−z1=x+yi. What is the value of x?
Answers: 2
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Given that z1=−34+36iz1=−34+36i and z2=21 +−6iz2=21+−6i, then z2−z1=x+yiz2−z1=x+yi. What is the val...
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