A line is parallel to y= 4x-2 and intersects the point (5,-11). what is the equation of this parallel line? y=4x + ?

The equation of line parallel to given line is: y=4x-31

Step-by-step explanation:

Given equation of line is:

The equation of line is in slope-intercept form so the co-efficient of x is the slope of the line.

Let m1 be the slope of the given line

then

m1 = 4

Let m2 be the line that is parallel to given line

As we know that the slopes of parallel lines is equal so

m1=m2 = 4

The slope-intercept form of equation of line is:

Putting the value of slope

to find the value of b, putting (5,-11) in the equation

Putting the value of b

Hence,

The equation of line parallel to given line is: y=4x-31

Keywords: Equation of line, slope

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

a

step-by-step explanation: