Please help MATH branliest Jaycie has a vip membership to a movie theater, so she pays 27 a year and 6$ for each movie she sees. claire doesnt have a membership so she pays 8.25$ each movie she sees. how many movies would they have to see in a year in order to pay the same amount that year?

What you would have to do for this problem is set up an equation for a year and equal them out. The equation would be 27+6x = 8.25x.

X = each visit to the movie.

Now all you have to do is solve the equation. Subtract 6x from 8.25x, and get 27=2.25x. Then, divide 2.25 from 27, and you would get your answer, which is 12. So, they would both have to see 12 movies to pay the same amount that year.

To check your work to see if you were right, you would plug in 12 as x, because that is the variable that represents the amount of visits to the movie. For Jaycie, the equation would be 27+6.00(12), and you would get 99, so she would pay $99 in total. For Claire, you would just do 8.25(12), which is also 99. That is how you know your answer is right.

4096 bacteria

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.