Write an equation of the line passing through the given point and satisfying the given condition. Give the equation (a) in slope-intercept form and (b) in standard form. (9,5); perpendicular to 3x-y=4

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

To find the slope(m), use the slope formula:

     And substitute/plug in the two points

(5, 9) = (x₁, y₁)

(9, 5) = (x₂, y₂)

m = -1        Now that you know the slope, plug it into the equation

y = mx + b

y = -1x + b   or   y = -x + b    To find b, plug in either one of the points into the equation, it doesn't matter which you use. I will use (5, 9)

9 = -(5) + b        Add 5 on both sides to get "b" by itself

9 + 5 = -5 + 5 + b

14 = b

y = -x + 14

Step-by-step explanation:

HOPE THIS HELPS!!!

(a) in slope-intercept form

Step-by-step explanation:

Find the slope of the line. To find the slope of the given line we need to get the line into slope-intercept form (y = mx + b), which means we need to solve for y: The slope of the line 3x – 5y = 9 is m = 3/5. Therefore, the slope of the line parallel to this line would have to be m = 3/5.

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1