Carrie needs to take a cab uptown and only has y dollars. The cab company charges a flat fee of $2.25 plus $0.55 per mile. If Carrie has $12.52 and she finds a cab company with the same flat fee that only charges $0.45 per mile, what is the maximum number of miles she will be able
to travel, to the nearest tenth of a mile?
what is the equation?

The maximum number of miles she will be able  to travel, to the nearest tenth of a mile is less than or equals to 22.8 miles.

She needs to take a cab and has y dollars. The company charges a flat rate of $2.25 plus $0.55 per mile. Therefore the equation will be

y = 2.25 + 0.55x

where

x = number of miles travelled.

Now she has $12.52 and she finds a cab company with the same flat rate and only charges $0.45 per mile. The maximum number of miles she will be able to travel to the nearest tenth of mile can be calculated below:

2.25 + 0.45x ≤ 12.52

x = number of miles travelled.

0.45x ≤ 12.52 - 2.25

x ≤ 10.27 / 0.45

x ≤ 22.8222222222

x ≤ 22.8 miles

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1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

the answer is simply just 6n add the two together as they have an n