What is the equation of the line in standard form?
x + 6y = 9
x−6y=−9x−6y=−9
3x−y=−63x−y=−6
3x + y = 6

x+6y=9 - > y= (-1/6)x+(3/2)

x - 6y=-9 - > y= (1/6)x+(3/2)

-9x - 6y = -9 - > y = (-3/2)x +(3/2)

3x - y = - 6 - > y= 3x + 6

-63x - y = - 6 - > y = - 63x + 6

3x + y = 6 - > y = -3x +6

Step-by-step explanation:

The standard form of the equation of a line is: y=ax+b

You seperate y from x and the constant value(the number) and then devide tge equation with the coefficient of y. Obviously it mustnt be division by zero.

the answer is d

step-by-step explanation:

you can also use mathway to get you answer + steps