2+3=8,
3+7=27,
4+5=32,
5+8=60,
6+7=72,
7+8=??

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

step-by-step explanation:

i'm not sure how to show the work for this

answer : c and d or 4(29 + 6)

4(29) + 4(6)