You want to create a six-digit passcode number which is of the form ABCDEF for your iPad. The digit ‘A’ is restricted to a number 1 through 9. The digits B, C, D and E can be any number, but they cannot repeat. The digits F has no restriction. How many choices are there for the digit "A"?

If you are just using the digits from 1 to 6, the answer would be 6*5*4*3*2*1 = 720, because you have 6 choices for the units digit, and then 5 choices left for the tens, and then 4 choices left for the hundreds and so on. Similarly, if all the digits from 1 to 9 were allowed (with no digit repeated), then the answer would be 9*8*7*6*5*4 = 60480.

The tricky part comes when the digit 0 is allowed: suppose that you wanted to form a 6-digit number using digits from 0,1,...,9 without repeating a digit. Then 0 could not be the leftmost digit. So, starting from the left, you would have 9 choices for the leftmost digit (not allowing 0), then 9 choices again for the next digit (0 is now allowable but not the previous digit), then 8 choices for the next digit and so on, for a result of 9*9*8*7*6*5 = 136080.

step-by-step explanation:

given expression is .

now we need to simplify the given expression .

we know that square root is equivalent to the power 1/2. so that means we can take half of the exponents to get the square root of given expression.

expanding that will give a very very large number so let's keep answer in exponent form.