A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Use equation, find the maximum height reached by the rocket, to the nearest 10th of a foot . Y=-16x^2+261x+130

Maximum height of the rocket = 1194.39 feet.

Step-by-step explanation:

The equation that shows the height of the rocket, y in feet, is related to the time after launch, x in seconds is as follows :

...(1)

We need to find the maximum height reached by rocket. For maximum height,

Put x = 8.15 s in equation (1).

So, the maximum height of the rocket is 1194.39 feet.

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )