Find the vertical asymptote(s) of f(x)= x^2 +3x+6/ x^2 -4

Hello,

f(x) = 2/x² + 3x - 10

Vertical asymptote is x=0

f(x) = x² + 6x -9/x - 2

No oblique asymptote.

= = = = = = = = = = = = = = = = = =

Indeed the problem would have been more interesting if you mattered enough to add some parenthesis...

= = = = = = = = = = = = = = = = = =

EDIT: ...so next time, bother a little to add the brackets where they need to be:

f(x) = 2/(x² + 3x - 10) = 2 / [(x + 5)(x - 2)]

Vertical asymptotes are x=2 and x=-5.

f(x) =(x² + 6x - 9) / (x - 2)

  = (x² - 2x + 8x - 16 + 7) / (x - 2)

 = x + 8 + 7/(x - 2)

Oblique asymptote is y=x+8

Precisely,

Step-by-step explanation:

0

Step-by-step explanation:

-13

step-by-step explanation:

f(x)=2x-5 for f(-4)

f(-4)   means let x=-4

f(-4) = 2(-4) -5

f(-4) =-8-5

      = -13

all it means is function 3