PLEASE HELP! Will give brainliest! Worth 30 points!

9514 1404 393

  a) 102.4

  b) 72.6

  c) 87.5

Step-by-step explanation:

The average value of a function over an interval is the integral of that function over the interval, divided by the width of the interval.

(a) The summer average is ...

__

(b) The winter average is similar:

__

(c) The annual average is the value added to the cosine function: 87.5

_____

Additional comment

The integral of the cosine function over the period of interest is ...

  ∫cos(2πx)dx = 1/(2π)sin(2πx)

For the limits x=1/2 and x=3/4, this becomes 1/(2π)(-1 -0) = -1/(2π).

When multiplied by -23.4(1/(1/4)), we get +23.4(2/π).

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints