16. In a volleyball match, Jenny serves the volleyball at 14 m/s, from a height of 2.5 m

above the court. The height of the ball in

h = -4.91 + 14t + 2.5, where h is the

height, in metres, and t is the time, in

seconds, after she serves the ball.

flight can be estimated using the equation

a) What is the maximum height of the

volleyball above the court? When does

this occur? Round answers to the

nearest tenth.

b) If a player on the other team contacts

the ball at a height of 0.5 m above the

court, how long does it take for the ball

to reach her? Round to the nearest

second.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.

answer: (3,11) is your answer.