Part A: Identify a pair of similar triangles. (2 points) Part B: Explain how you know the triangles from Part A are similar. (4 points) Part C: Find the distance from B to E and from P to E. Show your work. (4 points)

The answer is below

Step-by-step explanation:

Two triangles are said to be similar if the ratio of their corresponding sides are equal.

From the problem, since GRPC is a parallelogram, hence:

GC is parallel to RE and GR is parallel to CP.

∠GBC = ∠EBP (vertical opposite angles are equal)

∠BGC = ∠BEP (alternate interior angles are equal)

∠BCG = ∠BPE (alternate interior angles are equal)

Since, ∠GBC = ∠EBP, ∠BGC = ∠BEP and ∠BCG = ∠BPE, we can say that triangle BCG is similar to triangle BEP by the angle - angle - angle similarity postulate.

c) Since the triangle BCG is similar to triangle BEP, hence:

kbmflmklbhml; bmlzb; bdhzz

step-by-step explanation:

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.