Solve the triangle. A = 32°, a = 19, b = 14 (1 point) B = 23°, C = 125°, c ≈17.6 Cannot be solved B = 23°, C = 125°, c ≈29.4 B = 23°, C = 145°, c ≈23.5

The answer is below

Step-by-step explanation:

Given the triangle with: A = 32°, a = 19, b = 14

The sine rule states that for a triangle with lengths of a, b and c and the corresponding angles which are opposite the sides as A, B and C, then the following rule holds:

Given, that for triangle ABC; A = 32°, a = 19, b = 14. therefore:

A + B + C = 180° (sum of angles in a triangle)

32 + 23 + C = 180

55 + C = 180

C = 180 - 55

C = 125°

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

55? i think maybe

step-by-step explanation: