ABCD is a parallelogram. The diagonals of ABCD intersect at O.
OÀ=a and
OB = b
=
b
o
a) Express the vector CẢ in terms of a.
a
SI
А
D
b) Express the vector AB in terms of a and b.
c) Express the vector BC in terms of a and b.

50- 250 is correct i did that one too

step-by-step explanation:

b.-4 units

all you   do is count how many times you move

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

mathpapa

step-by-step explanation: