John has two different sugar syrups. Syrup A is 2 parts of sugar and 8 parts of water, and Syrup B is 3 parts of sugar and 5 parts of water. How much of each should john mix together to get 280 quarts of syrup that is 3 parts sugar and 7 parts water.

Volume of syrup A = 120 quarts

Volume of syrup B = 280 - 120 = 160 quarts .

Step-by-step explanation:

Syrup A : 2 parts sugar , 8 parts of water .

Total = 10 parts

Syrup B : 3 parts sugar , 5 parts of water .

Total = 8 parts .

Mixture required 280 quarts , 3 parts sugar , 7 parts water

In 280 quarts , sugar = 280 x 3  / ( 3 + 7 )

sugar = 84 parts

Let volume of syrup A be x , volume of syrup B = 280 - x

sugar A =  2 x / 10 = 0.2 x

sugar B = 3 ( 280 - x ) / 8 = .375 ( 280 - x )

Total sugar =  .2 x + .375 ( 280 - x ) = 84 .

.2 x + 105 - .375 x = 84

105 - 84 = .375 x - .2 x = .175 x

.175 x = 21

x = 21 / .175 = 120

Volume of syrup A = 120 quarts

Volume of syrup B = 280 - 120 = 160 quarts .

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

what are the statements

step-by-step explanation: