Mathematics, 31.01.2021 22:00, natajayd

If x=6 and y=2 then what is the value of 3x^2-4(2y-4/12)+8

Answers: 1

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Answers

answered: zamariahyou

304/3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Step-by-step explanation:

Step 1: Define

3x² - 4(2y - 4/12) + 8

x = 6, y = 2

Step 2: Evaluate

Substitute in variables: 3(6)² - 4(2(2) - 4/12) + 8Evaluate exponents: 3(36) - 4(2(2) - 4/12) + 8Multiply: 108 - 4(2(2) - 4/12) + 8(Parenthesis) Multiply: 108 - 4(4 - 4/12) + 8(Parenthesis - Fraction) Simplify: 108 - 4(4 - 1/3) + 8(Parenthesis) Subtract: 108 - 4(11/3) + 8Multiply: 108 - 44/3 + 8Subtract: 280/3 + 8Add: 304/3

answered: Guest

answer

a,b, and d

explanation

a reflection angle is more than

$\pi \: radians$

but less than;

$2 \pi \: radians$

an angle that measures

$\frac{4 \pi}{3} \: radians$

is a reflex angle.(true)

an angle that measures less than

$\frac{\pi}{2}$

is acute.(true)

provided we are considering angles greater or equal to zero.

an acute angle lies in the range.

$0 \leqslant \theta \: < \frac{\pi}{2}$

an obtuse angle is less than 180° but more than 90°

an angle that measures 300° is obtuse (false)

an angle that measures 65° is an acute angle.(true)

answered: Guest

the square root of what number? if you add that, then someone will probably answer the question.

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If x=6 and y=2 then what is the value of 3x^2-4(2y-4/12)+8...