So far this basketball season, Sherita made 46 of her first 60 free throws, giving her a free-throw average of
about 76.7%. What is the minimum number of free
throws she would need to make from now on in order
to have a free-throw average of at least 80% ?

Sherita would need to make 10 free throws

Step-by-step explanation:

Proportions

Sherita made 46 of her first 60 free throws in this basketball season. Calculating the average we get:

Sherita wants to have a free throw average of at least 80% in her next x free throws. This means she will have 46+x made throws out of 60+x total throws. For this new performance, the new average would be:

And we equate it to 80% (0.8 in decimal):

Multiplying by 60+x:

Operating:

Subtracting 46 and 0.8x:

0.2x=2

Dividing by 0.2

x = 10

Sherita would need to make 10 free throws

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

probably .5

i can on others if necessary.