Please answer this co-ordinate geometry year 10 exam question.

The distance between points A and B is 32 units.

Step-by-step explanation:

The general equation for a line in slope-intercept form is:

y = a*x +b

Where a is the slope, and b is the y-intercept.

We know that two lines are parallel if the lines have the same slope and different y-intercept.

Now, in this case we have the line:

5*x + 4*y = 16

We can rewrite this in slope-intecept form if we isolate the "y" in the left side:

4*y = -5*x + 16

y = (-5/4)*x + 16/4

y = (-5/4)*x+ 4

The slope is (-5/4) and the y-intercept is 4.

We know that line L₂ is parallel to this line, then this line will also have a slope equal to (-5/4) and a y-intercept equal to c.

y = (-5/4)*x + c

And we know that this line passes through the point (8, 15)

This means that when x = 8, the value of y must be 15.

We could just replace these two values in the above equation to find the value of c.

15 = (-5/4)*8 + c

15 + (5/4)*8 = c = 25

Then the line L₂ is:

y = (-5/4)*x + 25.

Now, we know that this line passes the x-axis at the point A.

The line will pass through the x-axis when y = 0, then we need to find the value of x such that y = 0.

0 = (-5/4)*x + 25

(5/4)*x = 25

x = 25/(5/4) = 20

Then point A is the point (20, 0)

And point B is when the line passes through the y-axis, this is when x = 0.

y = (-5/4)*0 + 25

y = 25

Then point B is the point (0, 25)

Now we want to find the distance between points A and B, which is equal to the distance between points (20, 0) and (0, 25).

When we have two points (a, b) and (c, d), the distance between them is:

distance = √( (a - c)^2 + (b - d)^2)

In this case, the distance between (20, 0) and (0, 25) is:

distance = √( (20 - 0)^2 + (0 -25)^2) =  32

The distance between points A and B is 32 units.

mx+89b(-98)nb

step-by-step explanation: