Aaron invested $570 in an account paying an interest rate of 7% compounded continuously. Assuming no deposits or withdrawals are made, how much money, to the nearest dollar, would be in the account after 8 years?

The amount of money that would be in the account after 8 years is approximately $998

Step-by-step explanation:

The given parameters for the compound interest investment are;

The amount Aaron invested = $570

The interest rate of the investment = 7%

The mode of compounding of the interest = Continuously

The number of years the amount is invested = 8 years

For a compounded continuously interest rate, we have;

Where;

A = The future value =The amount realized from the investment after the time of investment

P = The initial value = The principal amount invested

e = Euler's number = Mathematical constant

r = The interest rate = 7%

t = The time of investment = 8 years

Therefore, by substituting the known values, we have;

The amount of money that would be in the account after 8 years to the nearest dollar = The future value of the investment = A ≈ 998

The amount of money that would be in the account after 8 years to the nearest dollar ≈ $998.

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step-by-step explanation:

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a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: