The formula for the area of a triangle is Area = 1 2 × base × height. How much greater is the area of Triangle B than the area of Triangle A? A. 4 cm2 B. 5.9 cm2 C. 11.8 cm2 D. 23.6 cm2

Hello your question is not well written hence I will given a general answer with some assumptions

lets assume ; Triangle A : height = 4 , base = 2

                      Triangle B : height = 6 , base = 4

Step-by-step explanation:

Given data :

Triangle A : height = 4 , base = 2

Triangle B : height = 6 , base = 4

Area of triangle = 1/2 bh

Area of triangle of A = 1/2 * 2 * 4 = 8/2 = 4 cm^2

Area of triangle of B = 1/2 * 6 * 4 = 24/2 = 12 cm^2

Hence the area of triangle B is greater than triangle A by

= 12 - 4 = 8cm^2 ( apply the same principle to the complete question and you will get your answer )

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.