The length of a pair of corresponding sides of two similar ∆'s are 3 cm and 11 cm. If the area of the first ∆ is 18 cm^2 find the area of the second ∆.

The area of the second triangle is 242 cm²

Step-by-step explanation:

In the similar triangles

∵ The length of a pair of corresponding sides of two similar ∆'s are

   3 cm and 11 cm

→ Find the ratio of the corresponding sides

∴ The ratio of their corresponding sides =

∵ The area of the first ∆ is 18 cm²

→ Use the second rule above

∵ =

∵ A1 = 18 cm²

→ Substitute it in the ratio above

∴ =

→ By using the cross multiplication

∵ A2 × 9 = 18 × 121

∴ 9A2 = 2178

→ Divide both sides by 9

∴ A2 = 242 cm²

∴ The area of the second triangle is 242 cm²

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

answer: 800

step-by-step explanation: