HELP PLEASE :(
Match the expression to the sequence..

3x^2+3
2x^2-1
x^2+2

6,15,30,51
3,6,11,18
1,7,17,31

3x^2 + 3  -->  6, 15, 30, 51

2x^2 - 1    -->  1, 7, 17, 31

x^2 + 2     -->  3, 6, 11, 18

Step-by-step explanation:

Let's start with the first equation; 3x^2 + 3

Substitute 1 (the first digit in a sequence) for x.

3(1^2) + 3

3(1) + 3

3 + 3 = 6

3(2^2) + 3 Then the second digit.

3(4) + 3

12 + 3 = 15

Since the two numbers we have so far are 6 and 15, there is only one sequence this could match. 6, 15, 30, 51.

2(1^2) - 1

2(1) - 1

2 - 1 = 1

This equation represents 1, 7, 17, 31.

These same steps apply to the other equation as well.

1^2 + 2, then 2^2 + 2, then 2^2 + 2, and so on. (But we don't need to do extra work to figure that out.)

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5