Please help me with this precal problem :) a building casts a 121.6 foot shadow when the sun is 81.7 degrees above the horizon.

how tall is the building?
and at what value of theta will the shadow be twice as long as the building?

thank you so much! God bless!

Step-by-step explanation:

Draw a picture.

θ = 81.7°

tanθ = height/121.6

height = 121.6tanθ ≅ 833.5

The building is 833.5 ft high.

:::::

When shadow is 2×121.6 = 243.2 ft long, tanθ = height/243.2

θ = arctan(height/243.2) ≅ 73.7°

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

according to the triangle sum theorem, all the angles in a triangle must add up to 180 degrees. if we know one angle is already 90, we do 180-90=90. the other 2 angles must add up to 90, exactly.

step-by-step explanation: