(a) 2r + y = 12 (c)r + 3y = 8 (e) x = 7 (d) (f) 2y = 5 Find the equation of a line passing through (5.-6) perpendicular to: (a) 2x + y = 12 (b) 3x + 5y = 7 c) x + 3y = 8 (d) 7x - 12y = 5 ) 2y = 5 (f) = 7 1.8 She The dist from the D Find the throught then find EX and the equation of the line connecting the points of intersection of: x+y=4 3x - y = 12 (b) Sy = x - 9x and x=6 v=-6 2x = 1 Sy=x² – 9x x=3 12 -1) find the

man its nopq i just guessed and got it right so uhh

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step-by-step explanation:

what is the graph

step-by-step explanation:

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: