3. Q3) What is the smallest number of identical squares
that will fit in this rectangle?

Minimum 3 squares.

Step-by-step explanation:

Let the number of identical squares that will fit in the rectangle = x

Sum of the area of the squares = Area of the given rectangle

x(Side length of the square)²= (length of the rectangle × width of the rectangle)

x(S)²= (40 × 90)

x(S)²= 3600 cm²

For the minimum numbers of the squares,

If x = 1,

S = √3600 = 60 cm

But the length of the rectangle is 40 cm, so can't be fitted in the rectangle.

If x = 2,

2S² = 3600

S² = 1800

S = √1800

S = 42.43 cm

Since, length of the rectangle is 40 cm, so the given square can't be fitted in the rectangle.

If x = 3,

3S² = 3600

S² = 1200

S = √1200

  = 34.64 cm

Therefore, minimum 3 squares can be fitted in the given rectangle.

i understand 100% 10/10 hit or miss?

step-by-step explanation:

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).