For each of the following equations, give the centre and radius of the circle. a)x^2 + y^2 = 25 b) x^2 + y^2= 1
d) (x - 5)^2 + (y-3)^2 = 81 e) (x+2)^2 + (y-1)^2 = 9
g) (x + 1)^2 + (y + 3)^2 = 49 h) x^2+ y^2 = 6.25

a) Center is (0,0) and radius r = 5

b) Center is (0,0) and radius r = 1

d) Center is (5,3) and radius r = 9

e Center is (-2,1) and radius r = 3

g) Center is (-1,-3) and radius r = 7

h) Center is (0,0) and radius r = 2.5

Step-by-step explanation:

a)

Given circle  x² + y² = 25

The standard form of circle equation is

                   ( x-h)² +(y-0)² = r²

Center is (0,0) and radius r = 5

b)

Given circle  x² + y² = 1

The standard form of circle equation is

                   ( x-h)² +(y-0)² = r²

Center is (0,0) and radius r = 1

d)

Given circle  (x-5)² + (y-3)² = 81

The standard form of circle equation is

                   ( x-h)² +(y-0)² = r²

                   (x-5)² + (y-3)² = 9²

Center is (5,3) and radius r = 9

e)

Given circle  (x+2)² + (y+1)² = 9

The standard form of circle equation is

                   ( x-h)² +(y-0)² = r²

                  (x+2)² + (y+1)² = 3²

Center is (-2,-1) and radius r = 3

g)

Given circle  (x+1)² + (y+3)² = 49

The standard form of circle equation is

                   ( x-h)² +(y-0)² = r²

                  (x+1)² + (y+3)² = 7²

Center is (-1,-3) and radius r = 7

h)

Given circle  x² + y² = 6.25

The standard form of circle equation is

                   ( x-h)² +(y-0)² = r²

   Given circle  x² + y² = (2.5)²

Center is (0,0) and radius r = 2.5

it would open into a square depending on the type of envelope i’m not sure about the second part

the domain of a function is the set of input values, x , for which a function is defined. the domain is shown in the left oval in the picture below. the function provides an output value, f(x) , for each member of the domain.