After visiting the Needleton Natural Museum, Irma was so fascinated by the reptile exhibit that she got her very own pet lizard. Irma bought a terrarium shaped like a rectangular prism
for her lizard to live in. The terrarium is 20 inches long, 15 inches wide, and 12 inches tall.
Which equation can you use to find the volume of the terrarium, V?
V = 20 . 15. 12
20. 15 = 12.V
Sm
out
What is the volume of the terrarium?
Write your answer as a whole number or decimal. Do not round.
cubic inches

yes

step-by-step explanation:

yes

- (2, -7)

- lines r and s and lines t and u must be parallel

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

the answer is -1 1/5, also a

hope i

-lavira : )