PLEASE HELP 8 ml of a 80% acid solution was mixed with 12 ml of a 20% acid solution. What is the percentage of acid in the new solution?

44%

Step-by-step explanation:

So you have 2 bottles. One bottle is 8ml and is 80% acid. the other is 12 ml and is 20% acid.

This means there's 6.4 ml of acid in bottle 1(8*0.8) and 2.4 ml of acid in the other one(12*0.2).

The total amount of liquid is 8+12 = 20

The total amount of acid is 6.4+2.4 = 8.8

Percentage of acid in the new solution is 8.8/20 = 0.44 = 44%

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.

the final price would be 29.6925

step-by-step explanation:

39.59 minus 25% equals 29.6925