Mathematics
Mathematics, 08.11.2019 03:31, vanessajimenez361

Erica solved the equation βˆ’5x βˆ’ 25 = 78; her work is shown below. identify the error and where it was made.

βˆ’5x βˆ’ 25 = 78
step 1: βˆ’5x βˆ’ 25 βˆ’ 25 = 78 βˆ’ 25
step 2: βˆ’5x = 53
step 3: negative five times x over negative five = fifty-three over negative five
step 4: x = negative fifty-three over five

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Erica solved the equation βˆ’5x βˆ’ 25 = 78; her work is shown below. identify the error and where it was made. (5 points) βˆ’5x βˆ’ 25 = 78 step 1: βˆ’5x βˆ’ 25 βˆ’ 25 = 78 βˆ’ 25 step 2: βˆ’5x = 53 step 3: = step 4: x = step 1: she should have added 25 to each side. step 1: she should have divided both sides by βˆ’5. step 3: she should have divided both sides by βˆ’5. step 3: she should have multiplied both sides by βˆ’5
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Erica solved the equation βˆ’5x βˆ’ 25 = 78; her work is shown below. identify the error and where it was made. βˆ’5x βˆ’ 25 = 78 step 1: βˆ’5x βˆ’ 25 βˆ’ 25 = 78 βˆ’ 25 step 2: βˆ’5x = 53 step 3: negative five times x over negative five = fifty-three over negative five step 4: x = negative fifty-three over five step 1: she should have added 25 to each side. step 1: she should have divided both sides by βˆ’5. step 3: she should have divided both sides by βˆ’5. step 3: she should have multiplied both sides by βˆ’5.
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