The length of a rectangle is given by (x+9) feet and the width is (x+2) feet. If the area is 60 square feet, what are the length and width?

The length of the rectangle  = 12 feet

The width of the rectangle  = 5 feet

Step-by-step explanation:

Step(i):-

Given that the length of the rectangle = (x+9)feet

Given that the width of the rectangle = (x+2)feet

Area of the rectangle = 60 square feet ...(i)

we know that

Area of the rectangle = length × width

                                     = (x+9)(x+2) (ii)

Equating (i) and (ii) , we get

                   (x+9)(x+2) = 60

            ⇒ x² + 2x +9 x +18 =60

            ⇒ x² +11 x +18-60 =0

          ⇒  x² + 11 x -42 =0

          ⇒ x² +14 x -3 x - 42 =0

        ⇒  x (x+14) -3(x+14) =0

          ⇒ (x -3) ( x+14) =0

        ⇒  x -3 =0 and x+14 =0

     ⇒   x=3 and x=-14

step(ii):-

we choose value x =3

The length of the rectangle = (3+9) = 12 feet

The width of the rectangle = (3+2) = 5 feet

Final -

The length of the rectangle  = 12 feet

The width of the rectangle  = 5 feet

asdasdsad

step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a