the area of an isosceles triangle is 60 CM square and its base is 10 cm find the length of the equal sides

Step-by-step explanation:

Area = (1/2) *b*h

60 =(1/2)*10h

120 =10h

h=120/10

h= 12 cm

From the figure,

AB=BC(since the given triangle isosceles).

AE is perpendicular to BC.

BE =EC = 5cm ( since is AE bisects BC)

AB= h=12cm (height of the isosceles triangle)

Applying Pythagoras theorem in triangle ABE,

AB² = BE²+ AE²

AB² = 5²+12²

AB² = 169

AB =√169

AB= 13 cm

Hence AB=BC =13cm

Length of equal sides =13cm

answer: add the !

step-by-step explanation: then we will answer

its an acute right triangle

step-by-step explanation: