The height of a rocket, launched from the ground, is given by the function y = 30t − 5t^2, where y is in meters and t is in seconds. An observer is sitting at ground level a distance d from the launch point. If r is the distance between the observer and where the rocket is, show that dr/dt = ((30t − 5t^2)(30 − 10t))/(sqrt((30t−5t^2)^2+d^2)). Show all your work.

step-by-step explanation:

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answer: can you show the options ?

step-by-step explanation:

it is definatly the 3rd one. very much looks like it, for a good chance, the third one would be best for you.

8(4)^8=72^feet to say that the total can conclude to 8(4) which as you know would mean 8 x 4. that equals 32w. 32^ could make a 72 answer as well. but your coefficent will remain w so your answer is 72w.

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