A piece of paper measures 8.5 inches by 11 inches. Mrs. Wickowitz wants to hang paper on a bulletin board that has a height of 24 inches and an area of 1,728 square inches. Which inequality best represents the possible whole number of papers, p, that Mrs. Wickowitz could hang.

  D.  p ≤ 24

Step-by-step explanation:

The area of a piece of paper is 8.5·11 = 93.5 square inches, so the area of the bulletin board is that of ...

  1728/93.5 ≈ 18.48

pieces of paper.

The solution is a number greater than 18, so selection D is the only viable choice.

___

The bulletin board is 24 inches high and 1728/24 = 72 inches wide. If Mrs. Wickowitz hangs the papers "sideways", then 3 of them will cover 25.5 inches vertically, and 7 of them will cover 77 inches horizontally. That's 3·7 = 21 whole sheets of paper. That, too, matches selection D.

your exact question is kind of difficult to understand, so maybe an example will explain what you're supposed to do? i'll work through the first problem on the worksheet.

suppose you have a tray of 652 brownies, and you have 5 friends that you want to feed without picking favorites. how many brownies can you dole out to each of your friends in equal amounts? how many will be left over for you to eat?

what you're doing here is finding a way to arrange the number 652 as the sum of integer multiple of 5 and some remainder:

here ("q" for quotient) is the number of brownies each of your friends get, and is the remainder. that's the basic idea behind division.

we break up the number 652 into parts so that the leading digit stands on its own:

652 = 600 + 52

first we check if it's possible to hand out exactly 100 brownies to each friend. with 5 friends, this means we want to know if we can take out 500 brownies from the tray. we can do this 1 time because we have 600 brownies to take from, and when we do that we're left with 100 + 52 brownies to divvy up. so we know that

652 = 1*500 + 152

next we want to know if it's possible to hand out exactly 10 brownies per friend. if we can, we have to remove 50 brownies from the tray each time until we can't. we have 152 brownies left, and we know that 3(50) = 150, so

152 = 3*50 + 2

now we have 2 brownies left in the tray. is it possible to hand 1 out to each of your 5 friends? no, you'd need a minimum of 5 brownies to do that. so the last 2 are yours.

putting everything together, we found that

652 = 1*500 + 3*50 + 2

and we can rearrange this to write

652 = 5*100 + 5*30 + 2

652 = 5(100 + 30) + 2

652 = 5*130 + 2

so and .

you might be more accustomed to the table depicting the algorithm. that's just a compact way of organizing what we've done above. you can consult the image i've attached below.

dont't really have enough info here but its likely

sss for the three sides being congruent ( its stands for side side side)

or

sas   for side angle side.   so a side is congruent and and angle and a side