Which of the following completes the proof? Triangles ABC and EDC are formed from segments BD and AC, in which point C is between points B and D and point E is between points A and C. Given: Segment AC is perpendicular to segment BD Prove: ΔACB ~ ΔECD Reflect ΔECD over segment AC. This establishes that ∠ACB ≅ ∠E'C'D'. Then, . This establishes that . Therefore, ΔACB ~ ΔECD by the AA similarity postulate. translate point E' to point A; ∠E'D'C' ≅ ∠ABC translate point D' to point A; ∠E'D'C' ≅ ∠BAC translate point D' to point A; ∠D'E'C' ≅ ∠BAC translate point E' to point A; ∠D'E'C' ≅ ∠BAC